Chem 2320 Quiz 1 Key

Instructions: This quiz is open-book. You may use any book, magazine, or other printed or web-based materials you feel are helpful. You may discuss this quiz with other members of this immediate class and section. I will award extra credit (5 pts) to those who work in groups of 2-5 and who submit a group quiz. You may not consult with anyone outside of this immediate class and section about this quiz. You must show all your work for full credit, or to receive partial credit if you make a mistake.

1. (10 points) By and large, this information should be found in your notes. If not, check the online review notes.
2. (5 points) By and large, this information should be found in your notes. If not, check the online review notes.

3. (5 points) To summarize very briefly: as is shown on p. 197 for 2-bromo-2-methylbutane, the dissociation results in formation of a Lewis base, the bromide ion, and a Lewis acid, the resulting carbonium ion. The acidic carbonium ion reacts with ethanol, which behaves as a Lewis base as it donates an electron pair to a hydrogen atom.

   In the reaction of t-butyl bromide depicted on p. 316, as is the case for 2-bromo-2-methylbutane, the dissociation results in formation of a Lewis base, the bromide ion, and a Lewis acid, the resulting carbonium ion. The acidic carbonium ion reacts with water, a Lewis base. During the transfer of electrons from water to the carbonium ion, the water's oxygen atom becomes itself a Lewis acid, which subsequently reacts with a second water molecule in yet another Lewis acid-base reaction. Hydronium ion is formed as the product of the reaction.