Chapter 21
Nuclear Chemistry
Chapter 21 suggested problems:
Interesting links:
Interactive
Chart of Nuclei at http://www.nndc.bnl.gov/nudat2/index.jsp
Wikipedia
Isotope Table at http://en.wikipedia.org/wiki/Isotope_table_%28divided%29
Exploring
the Table of Isotopes at http://ie.lbl.gov/education/isotopes.htm
The Isotopes Project
Home Page at http://ie.lbl.gov/ip.html
Historical
Chart of the Nuclides (PDF, 241 kb) at http://ie.lbl.gov/toipdf/history.pdf
Class Notes
- Radioactivity
- Two types of radiation - electromagnetic and ionizing
- Electromagnetic radiation: a consequence of the disturbance
of electromagnetic fields, with the resulting emission of photons
of varying energies which in turn form the electromagnetic spectrum
- Ionizing radiation: generally the result of events within
the nuclei of atoms which result in the emission of particles,
often charged particles, which collide with neutral particles
as they travel which are ionized as a consequence of the collisions
- Nucleons: particles within the nucleus (protons and neutrons)
- Nuclei that are radioactive are called radionuclides, and
the atoms containing radionuclides are called radioisotopes
- Radioactive emissions: an unstable nucleus emits one or more
particles and is converted into a more stable isotope of a different
element
- Alpha decay
- A nuclear event that results in the ejection of an alpha
particle (a-particles)
- a-particles: two protons, two neutrons
- a-particles are heavy but lack penetrating power: can be
stopped by several sheets of paper
- Alpha decay result in the conversion of the parent element
into a new element (transmutation) with an atomic number
lessened by two (i.e. two fewer protons) and with an atomic
mass lessened by four (i.e. two fewer protons and two fewer
neutrons, or four fewer nucleons)
- Nuclear equation: 22688Ra -> 42a
+ 22286Rn
- Beta decay
- A nuclear event that results in the decay of a neutron into
a proton and a high energy electron (b-particle) which is
ejected from the nucleus
- The force responsible for holding protons and electrons
together in a neutron is called the Weak Force
- b-particles are less massive than a-particles but have much
higher energy and are more penetrating (e.g., 0.3 cm thickness
of Al)
- The atomic mass of the element stays the same but the atomic
number increases by one
- Nuclear equation: 23490Th -> 0-1b
+ 23491Pa
- Positron emission
- A nuclear event that results in the decay of a proton into
a neutron and a high energy anti-electron (positron) which
is ejected from the nucleus
- Positrons are the anti-matter equivalent of electrons, i.e.,
have the same mass as an electrons but have a +1 charge
- Penetration???
- The atomic mass of the element stays the same but the atomic
number decreases by one
- Nuclear equation: 20784Po -> 0+1b
+ 20783Bi
- Electron capture
- A nuclear event in which an inner shell electron is captured
by the nucleus, which results in the conversion of a proton
into a neutron and a high energy anti-electron (positron)
which is ejected from the nucleus
- The atomic mass of the element stays the same but the atomic
number decreases by one
- Nuclear equation: 74Be + 0-1b
-> 73Li
- Gamma ray emission
- Gamma radiation is made of high energy photons
- Almost always accompanies other radioactive events and is
equal to the energy lost when unstable nuclei rearrange themselves
into more stable configurations
- Extremely high energy, requires several mm of Pb, a foot
or more of concrete, etc. to stop
- Since photons are without mass or charge, photon emission
does not change either the atomic number or the atomic mass
- As a consequence, the emission of gamma particles is not
shown when writing nuclear equations
- Radioactive decay
- Nucleons are held together by the Strong Force, independent
of which neutrons seem to act as buffers between the protons
- Just as electrons arrange themselves into shells based on
their energy, so do nucleons into groups following similar rules
("Particle Explosion:" 58)
- Stability rules (BLB: 810ff)
- Magic numbers: nuclei with 2, 8, 20, 28, 50, or 82 protons
- or - with 2, 8, 20, 28, 50, 82, or 126 neutrons are more
stable than those that do not contain one or the other of
the number of nucleons
- In the lighter elements the n:p ratio is roughly 1:1, but
this ratio is about 1.25:1 in elements with A.N. of 25-45,
about 1.4:1 in elements with A.N. of 45-65, and about 1.5:1
in elements with A.N. of 65-84
- Nuclei above the stable ratio tend to lower the ratio through
beta decay and increasing the number of protons while decreasing
the number of neutrons
- Nuclei below the stable ratio tend to increase the ratio
through positron emission and increasing the number of neutrons
while decreasing the number of protons
- Above A.N. = 84 no nucleus is stable and all nuclei are
radioactive and decay to more stable nuclei, especially through
alpha decay
- Decay is generally a series of events from radioactive and
unstable toward stable isotopes
- Radioactive series: the transmutation of 23892U
to Pb is a 14 step process involving 8 alpha decays and 6 beta
decays (Wertz: 1093)
- 23892U -> 42a
+ 23490Th
- 23490Th -> 0-1b
+ 23491Pa
- 23491Pa -> 0-1b
+ 23492U
- 23492U -> 42a
+ 23090Th
- 23090Th -> 42a
+ 22688Ra
- 22688Ra -> 42a
+ 22286Rn
- 22286Rn -> 42a
+ 21884Po
- Etc.
- Half-lives (t1/2)
- The amount of time it takes for an amount "X" of
a radioactive element to decay to 1/2X
- 23892U (109 years) -> 42a
+ 23490Th (24 days)
- 23490Th -> 0-1b
+ 23491Pa (1.2 minutes)
- 23491Pa -> 0-1b
+ 23492U (105 years)
- 23492U -> 42a
+ 23090Th (104 years)
- 23090Th -> 42a
+ 22688Ra (1662 years)
- 22688Ra -> 42a
+ 22286Rn (3.8 days)
- 22286Rn -> 42a
+ 21884Po (3.0 minutes)
- Etc.
- Every radioisotope has its own individual decay constant "k"
that describes how rapidly or slowly the element decays
- ln (Nt / No) = -kt
- t1/2 = 0.693/k
- Examples
- The half-life of cobalt-60 is 5.3 years. How much of a 1.000
g sample of cobalt-60 is left after a 15.9 year period?
Since 15.9 is three half-lives, the sample has decreased to
(1/2) x (1/2) x (1/2) x 1.000 g = 0.250 g
- A wooden artifact from a Chinese temple has a 14C
activity of 24.9 counts per minute as compared with an activity
of 32.5 counts per minute for a standard of zero age. Given
that the half-life of 14C is 5715 years, calculate
the age of the artifact.
t1/2 = 0.693/k => k = 0.693/t1/2 = 1.213
x 10-4 yr-1
ln (Nt / No) = -kt => [ln (Nt
/ No)/-k] = t = [ln (24.9/32.5)/-1.213 x 10-4
yr-1] = 2196 years
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