Class Notes
- Energy: the capacity to do work
- The first law of thermodynamics - the conservation of energy: energy
can neither be created nor destroyed in chemical reactions, although
it can be transferred (heat, light) or transformed (from heat to light,
etc.)
- Potential energy: the energy a body has based on its position (gravitational
potential energy)
- Chemical potential energy: energy stored in chemical bonds
- Kinetic energy: energy associated with motion - translational, rotational,
vibrational, spin
- Internal energy: total energy, sum of potential and kinetic energies
- Measured in calories and Joules (4.184 J = 1 cal)
- Thermodynamics 101 - four important thermodynamic values
- During the course of a chemical reaction the internal energy changes
- ΔU = Ufinal - Uinitial
- ΔU = q + w = q - PΔV
- Definitions
- System: the part of the world in which we have an interest
- Surroundings: everything else
- Open system: a system that can exchange matter and energy with
the surroundings
- Closed system: a system that can exchange energy but not matter
with the surroundings
- Isolated system: a system that cannot exchange either matter
or energy with the surroundings
- Work: a transfer of energy that can be used to the change the
height of a weight somewhere in the surroundings
- In chemical reactions most work is PV work (expansion work),
work done by an expanding gas
- Heat: a transfer of energy as a result of a temperature difference
between the system and the surroundings
- Given ΔU = q + w = q - PΔV work and heat are equivalent
ways of the changing the internal energy of the system
- Sign conventions
- From system to surroundings: (-)
- From surroundings to system: (+)
- Enthalpy: in a system at constant pressure the heat associated changes
in internal energy is called enthalpy
- H = U + PV
- Hi = Ui + PVi
- Hf = Uf + PVf
- ΔH = Hf - Hi = (Uf - Ui)
+ P(Vf - Vi) = ΔU + PΔV
- Since ΔU = q - PΔV in a system that does only PV work
on its surroundings, then
- ΔH = q + PΔV - PΔV = q
- Sign conventions
- Exothermic (-) - heat flows from system to surroundings
- Endothermic (+) - heat flows from surroundings to system
- Types of enthalpy (different processes that, at constant pressure,
lead to changes in internal energy with consequent releases or absorbing
of energy)
- Enthalpy of reaction
- Enthalpy of formation
- Enthalpy of physical change (phase change)
- Enthalpy of ionization and enthalpy of electron gain
- Gibbs Free Energy - the energy available to do useful work changes
during the course of chemical reactions - depends on enthalpy, entropy,
and temperature
- ΔG = ΔH - TΔS
- -ΔG = spontaneous reaction; +ΔG = nonspontaneous reaction
- S = entropy - a measure of disorder, usually increases during
reactions (+) and is usually about 1% or less the size of ΔH
- Usually: if -ΔH then -ΔG; if +ΔH, then +ΔG
- Enthalpy of reaction (heat of reaction or ΔHrxn )
- General
- Since ΔHrxn = Hfinal - Hinitial,
then ΔHrxn = Hproducts - Hreactants
- Thermochemical equations: the coefficients of the balanced equation
represent the number of moles of reactants and products producing
the associated enthalpy change
- 2 H2 (g) + O2 (g) => 2 H2O(g);
ΔHrxn = -483.6 kJ
- The enthalpy of substances varies with their state of matter, it is
essential that the state of each reactant and product be specified
- Enthalpy is a extensive property - depends on the masses (the extent
of the samples) involved in the reaction (as compared to intensive properties
such as boiling point and melting point, which are independent of mass)
- 2 H2 (g) + O2 (g) => 2 H2O(g);
ΔHrxn = -483.6 kJ
- H2 (g) + ½O2 (g) => H2O(g);
ΔHrxn = -241.8 kJ
- 20 H2 (g) + 10 O2 (g) => 20 H2O(g);
ΔHrxn = -4836 kJ
- "Molar" enthalpy values and fractional coefficients
- Enthalpy is an state function, i.e., the enthalpy change for a phase
change or for a chemical reaction does not depend on the path taken
from initial conditions to the final conditions
- A path function depends on the way in which the final conditions
are reached from the initial conditions
- The road to the top of Pike's Peak: elevation vs. the length of
the road to the top
- ΔHrxn is equal in magnitude but opposite in sign
for the reverse reaction
- CH4 (g) + 2 O2 (g) => CO2 (g) +
2 H2O(l); ΔHrxn = -890 kJ
- CO2 (g) + 2 H2O(l) => CH4
(g) + 2 O2 (g); ΔHrxn = +890 kJ
- Stoichiometry
- Nitroglycerin (NG) is a powerful explosive that creates four different
gaseous products when detonated:
4 C3H5(NO3)3 (l) => 6
N2 (g) + O2 (g) + 12 CO2 (g) + 10
H2O(g); ΔHrxn = -5684 kJ
Calculate the enthalpy of reaction when 10.0 g of NG is detonated:
(10.0 g NG) x (1 mol NG / 227.1 g NG) x (-5684 kJ / 4 mol NG) = -62.6
kJ
- Calculate the enthalpy of reaction for the combustion of 100.0 g
of methane gas:
(100.0 g CH4) x ( 1 mole CH4 / 16.04 g CH4)
x (-890 kJ / mole CH4) = -5549 kJ
- Measuring enthalpy
- Specific heat and heat capacity
- Specific heat: the amount of heat required to raise the temperature
of 1.00 g of a substance by 1 K
- The greater the specific heat the more energy required to raise
the temperature of a substance
- The specific heats of solid aluminum, solid iron, and liquid water
are 0.90 J/g·K, 0.45 J/g·K, and 4.18 J/g·K
respectively. A 1.00 g sample of each substance is placed in identical
glass test tube. The test tubes are immersed for 5 minutes in boiling
water. At the end of the 5 minutes, the temperature of the three
substances is measured. Which of the three will be the warmest?
Which will be the coolest?
- Heat capacity: the amount of heat required to raise the temperature
of a substance by 1 K
- Molar heat capacity: the amount of heat required to raise the temperature
of 1 mole of a substance by 1 K
- Calculating heat flow: q = (SH) x (m) x (ΔT)
- How much heat is required to raise the temperature of 250.0 g of
liquid water from 22°C to a temperature of 100°C?
q = (4.18 J/g·K) x (250.0 g) x (100°C - 22°C / 1 K
/ 1°C) = 81588 J = 81.5 kJ
- An aluminum pan weighing 750.0 g is filled with boiling water. The
pan is emptied and placed in a freezer until it reaches the ambient
temperature of 0°C. How much heat does the pan emit?
q = (0.90 J/g·K) x (750.0 g) x (-100 K) = -67500 J = -67.5
kJ; since the heat is emitted the correct value is -67.5 kJ
- Calorimetry (qualitative)
- Hess's Law: if a reaction can be written as the sum of a series of two
or more reactions, the overall enthalpy of reaction is equal to the sum
of the enthalpies of reactions for each member of the series
- A + B => C + D; ΔHrxn = X kJ
C + D => E + F; ΔHrxn = Y kJ
E + F=> G + H; ΔHrxn = Z kJ
overall: A + B => G + H; ΔHrxn = X + Y + Z kJ
- CH4 (g) + 2 O2 (g) => CO2 (g) + 2
H2O(g); ΔHrxn = -802 kJ
2 H2O(g) =>2 H2O(l); ΔHrxn
= -88 kJ
CH4 (g) + 2 O2 (g) => CO2 (g) + 2 H2O(l);
ΔHrxn = -890 kJ
- The molar enthalpy of combustion of solid carbon to carbon dioxide
gas is -393.5 kJ / mole of carbon and the molar enthalpy of combustion
of carbon monoxide gas to carbon dioxide gas -283.0 kJ / mole of carbon
monoxide. Using these data calculate the enthalpy change for the combustion
of solid carbon to carbon monoxide.
C(s) + O2 (g) => CO2 (g); ΔH
= -393.5 kJ
CO(g) + ½ O2 (g) => CO2 (g); ΔH
= -283.0 kJ
C(s) + O2 (g) => CO2 (g); ΔH
= -393.5 kJ
CO2 (g) => CO(g) + ½ O2 (g) ;
ΔH = +283.0 kJ
C(s) + ½ O2 (g) => CO(g) ; ΔH
= -393.5 kJ + 283.0 kJ = -110.5 kJ
- Calculate ΔH for the reaction
2 C(s) + H2 (g) => C2H2 (g)
given the following reactions and their respective enthalpy changes:
C2H2 (g) + 5/2 O2 (g) => 2 CO2
(g) + H2O(l); ΔHrxn = -1299.6
kJ
C(s) + O2 (g) => CO2 (g); ΔHrxn
= -393.5 kJ
H2 (g) + ½O2 (g) => H2O(l);
ΔHrxn = -285.8 kJ
2 CO2 (g) + H2O(l) => C2H2
(g) + 5/2 O2 (g) ; ΔHrxn = +1299.6
kJ
2 C(s) + 2 O2 (g) => 2 CO2 (g); ΔHrxn
= -787 kJ
H2 (g) + ½O2 (g) => H2O(l);
ΔHrxn = -285.8 kJ
2 C(s) + H2 (g) => C2H2 (g)
; ΔH = +1299.6 kJ - 787 kJ - 285.8 kJ = +226.8 kJ
- Enthalpy of formation
- ΔH°f for a compound is the enthalpy change for
the reaction that forms one mole of the compound from its elements with
all elements in their standard states
- "°" indicates that calculations were made with the
substances in their standard states
- Usually 298 K and 1 atm
- If an element exists in two or more forms under standard conditions
the most stable form is used in the calculation of ΔH°f
- The stoichiometry is always for the formation of one mole of compound
(product)
- ΔH°f are always in units of kJ/mol of substance
formed
- ΔH°f of the most stable form of an element
in the standard state is 0 kJ/mol; no formation reaction is needed
if the element already exists in the standard state
- Using Hess's Law if we know ΔH°f for the participants
in a reaction (all of the reactants and all of the products) we can
calculate ΔHrxn
- ΔH°rxn = E (n)(ΔH°f prod)
- E (n)(ΔH°f rxt)
- Examples
- C3H8 (g) + 5 O2 (g) => 3 CO2
(g) + 4 H2O(l); ΔHrxn
= ?
3 C(s) + 4 H2 (g) => C3H8 (g);
ΔH°f = -103.85 kJ/mol
3 x (C(s) + O2 (g) => CO2 (g));
ΔH°f = -393.5 kJ/mol
4 x ( H2 (g) + ½O2 (g) => H2O(l));
ΔH°f = -285.8 kJ/mol
ΔH°rxn = [(3 moles) x (-393.5 kJ/mol) + (4 moles)
x (-285.8 kJ/mol)] - [(1 mole) x (-103.85 kJ/mol)] = -2219.85 kJ
- Calculate the standard enthalpy change for the combustion of 1 mole
of liquid benzene to carbon dioxide gas and liquid water.
C6H6 (l) + 15/2 O2 (g) => 6 CO2
(g) + 3 H2O(l);
ΔH°rxn = [(6 moles) x (ΔH°f
CO2 (g)) + (3 moles) x (ΔH°f H2O(l))]
- [(1 mole) x (ΔH°f C6H6 (l))
+ (15/2 moles) x (ΔH°f O2 (g))]
ΔH°rxn = [(6 moles) x (-393.5 kJ/mol) + (3 moles)
x (-285.8 kJ/mol)] - [(1 mole) x (+49.0 kJ/mol) + (15/2 moles) x (0
kJ/mol)] = -3267 kJ
- The standard enthalpy change for the reaction
CaCO3 (s) => CaO(s) + CO2 (g); ΔH°rxn
= +178.1 kJ
If the ΔH°f for solid calcium oxide is -635.5
kJ/mol and for carbon dioxide gas is -393.5 kJ/mol, what is the standard
enthalpy of formation of solid calcium carbonate?
ΔH°rxn = [(1 mole) x (ΔH°f
CaO(s)) + (1 mole) x (ΔH°f CO2
(g))] - [(1 mole) x (ΔH°f CaCO3 (s)
)]
[(1 mole) x (ΔH°f CaCO3 (s) )] = [(1
mole) x (ΔH°f CaO(s)) + (1 mole) x
(ΔH°f CO2 (g))] - [(1 mole) x (ΔH°f
CaCO3 (s) )] - ΔH°rxn
ΔH°f CaCO3 (s) = [(1 mole) x (-635.5
kJ/mol ) + (1 mole) x (-393.5kJ/mol)] - [ +178.1 kJ] = -1207.1 kJ
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