Chapter 4
Aqueous Reactions and Solution Stoichiometry
Chapter 4 suggested problems -
10th Ed. - 4.x: 15, 19, 21, 23, 29, 39, 43, 49, 51, 61, 63, 65, 67, 79, 110
11th Ed. - 4.x: 15, 19, 21, 23, 29, 39, 43, 49, 51, 61, 63, 67, 69, 81, 110
Class Notes
- General properties of aqueous solutions
- When anything dissolves in water it is said to be in aqueous solution
- Solution: a homogenous mixture consisting of a solvent and one or
more solutes
- Solvent: "the stuff that does the dissolving" and/or the
material present in greatest amount
- Solute: "the stuff that gets dissolved" and/or the material(s)
present in lesser amount
- When ionic compounds dissolve in water they dissociate i.e. they
break apart into ions
- Not all ionic compounds will dissolve in water
- Ions can serve as charge carriers, i.e., aqueous solutions of ions
will conduct electricity
- Electrolytes and nonelectrolytes
- Substances that dissolve and create electrically conductive aqueous
solutions are electrolytes
- If an ionic compound will dissolve in water it will almost certainly
ionize and behave as an electrolyte
- Most - but not all - molecular compounds do not conduct electricity
when they dissolve; substances that do not create conducting solutions
when they dissolved are called nonelectrolytes
- Examples
- NaCl (aq) => Na+(aq) + Cl-(aq)
- C6H12O6 (aq) => C6H12O6
(aq)
- Strong, weak, and nonelectrolytes
- Strong electrolytes - dissociate (ionize) ~100%
- This includes virtually all ionic compounds and molecular compounds
like HCl and other mineral acids
- Weak electrolytes - dissociate less than 100%, usually 1-10% or less
- The most common weak electrolytes are the organic acids
- Nonelectrolytes - do not dissociate
- This includes virtually all covalent compounds except organic acids
and bases
- Molecular and ionic equations
- Chemical equations are a shorthand way of describing a chemical reaction
- There are different types of chemical equations
- Molecular equations - all reactants and products are written as complete
molecules even though they may exist as ions in solution
- NaCl(aq) + AgNO3 (aq) => AgCl(s)
+ NaNO3 (aq)
- Complete ionic equations - strong electrolytes are written as ions if
they are in aqueous solution
- Na+(aq) + Cl-(aq) + Ag+(aq)
+ NO3-(aq) => AgCl(s) +
Na+(aq) + NO3-(aq)
- Net ionic equations - spectator ions are canceled and the actual reaction
that takes place is left
- Cl-(aq) + Ag+(aq) => AgCl(s)
- Examples
- Write the molecular, complete ionic, and net ionic equations for the
double-displacement reaction of barium nitrate and ammonium sulfide
- Ba(NO3)2 (aq) + (NH4)2S(aq)
=> BaS(s) + 2 NH4NO3 (aq)
- Ba2+(aq) + 2 NO3-(aq)
+ 2 NH4+(aq) + S2-(aq)
=> BaS(s) + 2 NH4+(aq) +
2 NO3-(aq)
- Ba2+(aq) + S2-(aq) =>
BaS(s)
- Write the molecular, complete ionic, and net ionic equations for the
double-displacement reaction of lithium sulfate and lead acetate
- Li2SO4 (aq) + Pb(C2H3O2)2
(aq) => PbSO4 (s) + 2 LiC2H3O2
(aq)
- 2 Li+(aq) + SO42-(aq)
+ Pb2+(aq) + 2 C2H3O2-(aq)
=> PbSO4 (s) + 2 Li+(aq) + 2 C2H3O2-(aq)
- SO42-(aq) + Pb2+(aq)
=> PbSO4 (s)
- Types of reactions
- Precipitation reactions - the mixing of two aqueous solutions of ionic
compounds may result in the formation of a new insoluble (will not dissolve)
ionic compound called a precipitate
- These reactions are generally - but not always - double displacement
reactions
- Double displacement reactions involve anion exchange between two ionic
compounds and are also known as exchange or metathesis reactions
- Solubility rules (p. 127, Table 4.1) make it possible to predict whether
or not an ionic compound is soluble or insoluble
- Note: these are general rules. Solubility is a little more involved
than this but these provide a very good general set of guidelines
- Rule 1: Group 1 cations and ammonium ion are always soluble
- Rule 2: acetates and nitrates are always soluble
- Rule 3: halogens are always soluble unless the cation is Ag+,
Hg22+, Hg2+, or Pb2+
- Rule 4: sulfates are always soluble unless the cation is Ag+,
Hg22+, Hg2+, Pb2+, Ca2+,
Sr2+, or Ba2+
- Rule 5: carbonates, phosphates, sulfides, and hydroxides are always
insoluble
- Examples: will a reaction occur if the aqueous solutions of the following
ionic compounds are mixed? Assume that if a reaction occurs it is a double-displacement
reaction:
- Ammonium phosphate and iron (III) nitrate
- Sodium iodide and mercury (II) acetate
- Ammonium sulfide and potassium hydroxide
- Silver (I) acetate and cesium sulfate
- Rubidium carbonate and chromium (III) chloride
- Gold (III) carbonate and nickel (IV) sulfide
- Acid-base reactions
- Acid-base definitions - we'll only worry about the Arrhenius definition
this semester
- Arrhenius: acid - H+ donor, base - OH- donor
- Brönsted-Lowry: acid - proton donor, base - proton acceptor
- Lewis: acid - electron pair acceptor, base - electron pair donor
- Strong and weak acids and bases
- Strong acids and bases dissociate nearly 100%
- Weak acids and bases dissociate less than 100%, usually 1-10% or less
- Note that "strong" and "weak" have little or no
correlation with the corrosiveness of the compound
- Strong acids: mineral acids - (nitric, sulfuric, hydrohalic, perchloric)
- Strong bases: Group I & II hydroxides
- Weak acids: hydrofluoric, phosphoric, organic acids
- Weak bases: amines
- Neutralization reactions of Arrhenius acids: double displacement, the
hydrogen ion and hydroxide ion combine and form water
- HCl(aq) + NaOH(aq) => H2O(l) + NaCl(aq)
- Salt - the ionic compound formed during a neutralization reaction
- Polyprotic acids and neutralization reactions
- H3PO4 (aq) + 3 NaOH(aq) => 3 H2O(l)
+ Na3PO4 (aq)
- Bases with multiple hydroxide groups and neutralization reactions
- 2 HCl(aq) + Ba(OH)2 (aq) => 2 H2O(l)
+ BaCl2 (aq)
- Gas forming reactions: only take place under a very limited set of circumstances
- One of the reactants must be an acid
- The anion of the other reactant must be either carbonate, sulfite, or
sulfide (this also includes bicarbonate and bisulfite)
- 2 H+(aq) + CO32-(aq)
=> H2CO3 (aq) => H2O(l)
+ CO2 (g)
- 2 H+(aq) + SO32-(aq)
=> H2SO3 (aq) => H2O(l)
+ SO2 (g)
- 2 H+(aq) + S2-(aq) =>
H2S(g)
- Reactions
- 2 HCl(aq) + Na2CO3 (aq) => 2 NaCl(aq)
+ H2O(l) + CO2 (g)
- 2 HNO3 (aq) + BaSO3 (aq) => Na(NO3)2
(aq) + H2O(l) + SO2 (g)
- 2 HBr(aq) + (NH4)2S(aq)
=> 2 NH4Br(aq) + H2S(g)
- Redox (oxidation-reduction) reactions
- Terms
- Oxidation-reduction reaction (redox reaction): a reaction in which
electrons are transferred between spp. and/or in which atoms involved
in the reaction change oxidation number
- Oxidation number: a concept devised as way of keeping track of electrons
in reactions: the actual charge on a monatomic ion, or the hypothetical
charge assigned to an uncharged atom using a set of rules
- Oxidation (oxidized): the loss of one or more electrons
- Reduction (reduced): the gain of one or more electrons
- Oxidizing agent: a chemical that oxidizes something else and reduces
itself
- Reducing agent: a chemical that reduces something else and oxidizes
itself
- Rules for determining oxidation numbers
- Rule 1: the oxidation number of atoms in their elemental state is
zero
- Rule 2: the oxidation number of a monatomic ion is equal to its charge
- Rule 3: the oxidation number of oxygen is always equal to -2 unless
in a peroxide (then -1)
- Rule 4: the oxidation number of hydrogen is always +1 unless in a
hydride (then -1)
- Rule 5: Fluorine always has an oxidation number of -1. The other halogens
always have an oxidation of -1 as anions in binary compounds. Halogens
listed as the first member of a binary molecular compound or involved
in oxyanions have positive oxidation numbers.
- Rule 6: for either a neutral compound or for any polyatomic ion, the
sum of the oxidation numbers of the atoms in the molecule is equal to
the net charge on the specie
- Examples of determining oxidation numbers:
- NO3-
- H2SO4
- Fe(OH)2
- Li3PO4
- HClO3
- W2(SO3)3
- Balancing simple redox equations: rules
- Assign oxidation numbers to all atoms in all reactants and products
- Break the reaction down into oxidation and reduction half-reactions
- Multiply if necessary to get the number of electrons in each half-reaction
to be equal
- Add the half-reactions together
- Predicting the outcome of redox reactions - the Activity Series
- The Activity Series is commonly taught in first semester Gen Chem
1 but is over-rated. Stay tuned for Gen Chem 2.
- Examples of balancing simple redox equations (single displacement reactions)
- 2 Ca(s) + O2 (g) => 2 CaO(s)
- Fe2O3(s) + 2 Al(s) => 2 Fe(s)
+ Al2O3 (s)
- Mg(s) + 2 HCl(aq) => MgCl2 (aq) +
H2 (g)
- Common types of redox reactions
- Combination reactions - two substances combine to form a third substance
(the formation of table salt from sodium and chlorine)
- Decomposition reactions - a single compound reacts to form two or
more new substances (the formation of hydrogen and oxygen from water)
- Displacement reactions (single displacement reactions) - an element
reacts with a compound and replaces an element in the compound
- Combustion reactions - a substance reacts with oxygen with the rapidly
release of heat and light energy - oxygen is the oxidizing agent in
combustion reactions
- Molar concentration and diluting solutions (various ways of expressing concentration
discussed in Chapter 13.4)
- Molarity - ratio of moles of solute dissolved per liters of solution:
M = moles solute / liters of solution
- Calculations:
- What is the molarity if you dissolve 2.0 moles of HNO3 in
1.00 liter of water?
- What is the molarity if you dissolve 2.0 moles of HNO3 in
0.500 liter of water?
- What is the molarity if you dissolve 2.0 moles of HNO3 in
5.00 liter of water?
- What is the molarity if you dissolve 25.0 g of HNO3 in 1.00
liter of water?
- 25.0 mL of 2.5 M solution contain how many moles of HNO3?
- 125.0 mL of 2.5 M solution contain how many grams of HNO3?
- Diluting solutions: M1V1 = M2V2
- If 25.0 mls of 12 M sulfuric acid is diluted to 500 mL, what is the
new concentration of the acid?
- If 125.0 mls of 2.5 M copper (II) nitrate solution is diluted to 1500
mL, what is the new concentration of the solution?
- To obtain 150 mls of 1.00 M ammonium hydroxide solution, how many mls
of 15 M solution must be used?
- Titrations
- A titration is a form of chemical analysis in which a solution with a
known concentration is used to determine the concentration of a chemical
in an unknown solution
- Note: used to determine amounts or concentrations, not chemical identity
of unknown substances.
- The known solution is called a standard solution or a standard titrant.
- A buret is used to deliver the titrant, and the unknown solution and
the titrant are mixed together as the titrant is added.
- Equivalence point: this is the point in a titration at which the amount
of titrant added is equal to the amount of unknown chemical in the solution
being titrated.
- The equivalence point is reached when there is a very specific physical
change in the mixture of titrant and unknown solution, such as a color
change or the formation of a preciptitate.
- Indicators: chemicals used to indicate when the equivalence point is
reached. Usually this indication is in the form of a color change.
- End point: the point at which an indicator's color change takes place.
Hopefully the equivalence point of the reaction and the end point of
the indicator coincide.
- Not all titration reactions require an indicator
- Types of titrations
- Acid-base
- Precipitation
- Redox
- Titration calculations
- A solution of HCl is standardized using solid sodium carbonate. If you
begin with 0.263 g of sodium carbonate and must add exactly 28.35 mL of
HCl to reach the equivalence point, what is the acid concentration?
- Procedure: dissolve the sodium carbonate in water, then add HCl from
a buret until the equivalence point is reached.
- Begin with a balanced equation for the reaction:
Na2CO3 (aq) + 2 HCl(aq) => 2 NaCl(aq)
+ H2O(l) + CO2 (g)
- (0.263 g S.C.) x (1 mol S.C./106.0 g S.C.) x (2 mol HCl/1 mol S.C.)
= 0.00496 mol HCl
- (0.00496 mol HCl/28.35 mL) x (1000 mL/1L) = 0.175 M HCl