Chapter 8
Gases, Liquids, and Solids
Chapter 8 suggested problems: 40, 46, 52, 54, 56, 66, 72, 74, 80,
86, 87, 88
Class Notes
- General gas properties
- Fluid, no fixed volume or shape, take the shape and volume
of the container
- Molecular level - particles are relatively far apart and generally
do not interact - reason for compressibility
- Temperature and pressure
- Temperature - a measure of how hot or cold something is;
there is a direct correlation between temperature and kinetic
energy
- K.E. = 3/2 kT (k = 1.38 x 10-23 J K-1)
- 1/2 mv2 = 3/2 kT
- mv2 = 3 kT
- v = (3 kT / m)1/2
- Pressure => P = F/A => P = (# of collisions) x (KE
of collisions) / area over which collisions occur
- lbs/in2
- atm (14.7 psi)
- bar (14.5 psi)
- Torr (T)
- mm Hg
- Pascals (Pa)
- 1 atm = 14.7 psi = 760 T = 760 mm Hg = 101,325 Pa
- STP - standard temperature and pressure - 1 atm and 273
K
- The Ideal Gas Law (Universal Gas Law)
- Ideal gases vs. real gases - no volume or interactions; real
gases are most like ideal gases at low P and high T
- The synthesis of work by Boyle, Charles, Gay-Lussac, and Avogadro
- Boyle's Law: P1V1 = P2V2
- Charles's Law: V1/T1 = V2/T2
- Gay-Lussac's Law: P1/T1 = P2/T2
- Avogadro's Law: V1/n1 = V2/n2
- PV = nRT
- P = pressure (atm)
- V = volume (L)
- n = number of moles (mol)
- T = temperature (K)
- R = gas constant = 0.0821 L atm / mol K
- Examples
- If 1.00 mole of a gas occupies a volume of 1.00 L at 298
K, what is the pressure inside the container? (24.46 atm)
- A 5.00 L container holds a gas at 810 T and 62 oC.
How many moles of gas are present? (0.194 moles)
- If you blow exactly 2.00 moles of air into a balloon at
a pressure of 780 mm Hg and at a temperature of 35 oC,
what volume must the balloon hold to keep from bursting? (49.3
L; volumes: 11" balloon - 11.4 L, 18" balloon -
50.0 L)
- 6.75 moles of an unknown gas occupy a volume of 13.3 L at
a pressure of 17.6 atm. What is the temperature of the gas?
(422.4 K)
- Determination of molar masses - can use the Ideal Gas Law
to find the molar mass of unknown substances
- n = number of moles = mass of substance / molar mass
- PV = gRT / MW
- examples
- 44.9 g of an unknown gas exert a pressure of 2.55 atm
within a 10.2 L container at 325 K. Is the unknown gas nitrogen
dioxide or sulfur dioxide? (mw = 46.06 g/mol; mw for NO2
= 46.01 g/mol, mw for SO2 = 64.06 g/mol)
- A damaged unmarked cylinder of compressed gas in found
in the ruins of the WTC. You suspect that the gas is either
argon, nitrogen, helium, or carbon dioxide. A 5.00 L mylar
bag is filled with the gas to a pressure of 1900 T at 298
K. When weighed, the mass of the gas is 20.42 g. What is
it? (mw = 39.97 g, Ar)
- Stoichiometry
- An 18" balloon has a volume of 50.0 L. How many grams
of water must be decomposed via electrolysis to fill the balloon
with hydrogen to a pressure of 1.05 atm at 298 K?
PV/RT = n = 2.146 moles hydrogen
2.146 moles hydrogen is generated by the decomposition of
38.7 grams of water
- The reaction of 75.0 g of iron (III) sulfide with excess
hydrochloric acid will produce what volume of gas at 755 T
and 293 K?
75.0 g iron (III) sulfide is equivalent to 1.082 moles hydrogen
disulfide; (26.2 L)
- Comparative calculations
- For any gas under any set of conditions PV = nRT
- for any gas in which the conditions change
- start: P1V1 = n1RT1
- finish: P2V2 = n2RT2
- Since R is constant in both cases
- R = (P1V1) / (n1T1)
- R = (P2V2) / (n2T2)
- (P1V1) / (n1T1)
= (P2V2) / (n2T2)
- This is Boyle's Law, Charles's Law, Gay-Lussac's Law, and
Avogadro's Law all rolled into one. If you remember this relationship
you don't need to remember all of the others.
- Examples
- 7.5 moles of a gas at 2.25 atm of pressure occupy a volume
of 2.00 L. If the gas is compressed to a volume of 1.00 L
what is the new pressure of the gas? (4.50 atm)
- A sample of gas at 373 K exerts a pressure of 1500 T. If
the temperature drops to 273 K, what will the new pressure
be? (1.44 atm)
- 10.0 moles of helium at 298 K occupy a volume of 20.5 L
at a pressure of 11.93 atm. If the temperature of the gas
increases to 328 K, how must the container volume change for
the pressure to remain the same? (22.56 L)
- A 3.6 mole sample of gas in a sealed vessel has a pressure
of 4.25 atm. If the number of moles of gas is increased to
4.9 moles, what will the new pressure be? (5.78 atm)
- 10.0 moles of a gas at 26.0 atm and 303 K occupy a volume
of 9.57 L. If the number of moles of gas is suddenly changed
to 15.0 moles while the temperature increases to 373 K and
the volume decreases to 5.00 L, what will the new pressure
in the container be? (91.89 atm)
- Dalton's Law of Partial Pressures
- If more than one substance is present in gaseous form, the
total pressure is the sum of pressures of all of the gases present
- The pressure each gas contributes to the total pressure is
called it's partial pressure
- PT = P1 + P2 + P3
+ . . . .
- Examples
- A sealed flask contains nitrogen at a pressure of 500 T
and oxygen at a pressure of 250 T. What is the total pressure
in the flask? (750 T)
- A 10.0 L flask contains 1.0 mole of carbon dioxide, 2.0
moles of methane, and 4.0 moles of water vapor. If the temperature
inside the flask is 303 K, what is the total pressure? (2.49
atm + 4.98 atm + 9.95 atm = 17.4 atm)
- Mole fraction - the ratio of the gas pressure of a single
component divided by the total pressure (P1 / PT),
or, the ratio of the number of moles of a single component divided
by the total number of moles (n1 / nT)
- States of matter, phase transitions, and enthalpies of changes
of state
- Gas: fluid; no fixed volume or shape; compressible; molecules
relatively far apart with little or no interaction
- Liquid: fluid; fixed volume but no fixed shape; molecules
close together (incompressible) and interact with each other
- Solid: fixed volume and shape; molecules close together (closest;
incompressible) and interact with each other
- Transitions
| s > l: melting |
l > s: freezing |
| l > g: vaporization |
g > l: condensation |
| s > g: sublimation |
g > s: deposition |
- Enthalpies of changes of state
- Attractive forces between molecules
- Intramolecular forces
- Based on electrostatic attraction - the attraction of oppositely
charged particles (protons and electrons)
- Coulomb's law: F = (kq1q2)/r2
- Intermolecular forces
- Still electrostatic but based on partial rather than full
charges, (generally) not as strong as intramolecular forces
- Covalent bonds and polar covalent bonds, dipole moments
- Covalent bonds: equally shared bonding electrons
- If the two bonding atoms are not the same element, they
will have different EN
- Implication: the bonding electrons will not be shared
equally
- Implication: slight positive and negative charges develop
on the bonding atoms
- Generalization: a molecule with one or more polar bonds
will itself be polar
- Exceptions due to molecular symmetry
- Polar molecules have a dipole moment - a numerical measure
of the magnitude of the charge and the distance between
the centers of positive and negative charge in the molecule
- Induced dipole - induced dipole interactions
- Also called London forces or dispersion forces
- Nature of dispersion forces
- All substances are capable of dispersion forces
- It is the only IM bonding force in non-polar molecules
- Weak because partial charges are involved and because
they are temporary
- Although a weak force it increases in strength as the
number of electrons in a substance increases (i.e., as the
MW increases) or as the size and/or surface area of a molecule
increases
- Polarizability - a measure of the ease of distortion of
an electron cloud
- Dipole - dipole interactions
- Nature of dipole - dipole interactions
- Only occur between permanently polar molecules
- Relatively strong because while partial charges are involved
they are permanent
- Relative strengths
- Hydrogen bonds - a special case of dipole-dipole interactions
- When H is bonded directly to N, O, or F the bond is so polar
(due to the magnitude of the EN differences) that a very strong
dipole-dipole bond - called a hydrogen bond -is formed
- While H-bonds are the strongest IM forces they are still,
on average, only 10-20% as strong as ionic and covalent bonds
- Orientation of molecules forming hydrogen bonds: how the molecules
align
- Interactions between H-bonding molecules and polar molecules
which cannot form H-bonds
- Liquids, physical properties, and intermolecular forces
- To predict the effect of IM forces on a substance need to
be able to accurately state the IM forces of which the substance
is capable
- Remember the general order: H-bonds > dipole-dipole > dispersion
forces
- Rank the following in order of the strength of the IM forces:
H2, CH4, CH2Cl2,
CH3OH
- CH2OHCHOHCH2OH, Ar, N2,
CH3CH2Cl, CH3OH
- The relative strengths of IM forces can be estimated by comparing
the boiling points of compounds
- For boiling to occur enough energy must be added the system
overcome the IM forces between the liquid molecules
- Three substances have boiling points of -30°C, 50°C,
and 175°C. Which has the strongest IM forces?
- "Like attracts like:" substances with similar IM
forces will mix, while substances with different IM forces will
not mix well, if at all
- Solutions - homogeneous mixtures
- Solvent
- Solute
- Solution
- Miscibility
- For substances to mix they must have similar IM forces
- Table salt - water
- Water - alcohol
- Water - oil
- Oil - vinegar
- Oil - hexane
- Oil - carbon tetrachloride
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